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A confined aquifer has a specific storage of 2.4 x 10-S ft and a thickness of 300 ft. How much water (in acre-ft) would it yield if the water declined 4.8 ft uniformly over a circular area with a radius of 1,500 ft?

Respuesta :

Answer:

water it yield is 244290.45 ft

Explanation:

given data

specific storage SS = 2.4 Ă— [tex]10^{-5}[/tex] ft

thickness b = 300 ft

water declined ΔH  = 4.8 ft

radius r = 1,500 ft

to find out

How much water  would it yield

solution

we know that

volume of water is

Vw = S × Area ×  ΔH    ..............1

here S = specific storage Ă— thickness

S = 2.4 Ă— [tex]10^{-5}[/tex] Ă— 300

S = 7.2 ×  [tex]10^{-3}[/tex]

and

area = πr² = π 1,500² = 7068589.471 ft²

so

volume of water is

Vw = 7.2 ×  [tex]10^{-3}[/tex]  × 7068589.471 ×  4.8

Vw = 244290.45

so water it yield is 244290.45 ft

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