1Makiya
1Makiya 1Makiya
  • 02-03-2020
  • Mathematics
contestada

Find sin A



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Hrishii
Hrishii Hrishii
  • 02-03-2020

Step-by-step explanation:

[tex] \sin A = \frac{BC}{AB} = \frac{20}{25} = \frac{4}{5} \\ [/tex]

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profarouk profarouk
  • 02-03-2020

Answer:

[tex]\frac{4}{5}[/tex]

Step-by-step explanation:

[tex]sinA = \frac{BC}{BA} = \frac{20}{25}=\frac{20:5}{25:5}=\frac{4}{5}[/tex]

Answer Link

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