Answer:
0.66 mol
Explanation:
Zero Gauge pressure = 14.7 psi
Pressure read = 173 psi
Actual pressure = 173 psi - 14.7 psi = 158.3 psi
P (psi) = 1/14.696 Â P(atm)
So, Pressure = 10.77 atm
Given that:
Temperature = 20 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15 Â
So, Â
Tâ = (20+ 273.15) K = 298.15 K
V = 1.50 L
Using ideal gas equation as:
[tex]PV=nRT[/tex]
where, Â
P is the pressure
V is the volume
n is the number of moles
T is the temperature Â
R is Gas constant having value = 0.0821 L atm/ K mol Â
Applying the equation as:
10.77 atm Ă 1.50 L = n Ă0.0821 L atm/ K mol  à 298.15 K
ân = 0.66 mol