A scuba diver is swimming at the depth shown, and then swims 0.5 foot toward the surface every 3 seconds. What is the location of the scuba diver, relative to the surface, after 15 seconds?

0.5 x 4 = 2 feet / 2 feet in 4 seconds
15 - 2 = 13
New depth: 13 feet

0.4 x 3 = 1.2 feet / 1.2 feet in 3 seconds
13 - 1.2 = 11.8
New depth: 11.8 feet

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fichoh fichoh · Answer 2 · 2021-10-29T12:01:43+02:00

The new location of the diver is the obtained by subtracting the height attained after 15 seconds from his initial depth. Hence, new location is 7.5 feets.

Assume the initial depth of the diver = 10 feets

The swim rate toward the surface every 3 second = 0.5 feets

The height climbed after 15 seconds can be calculated thus :

(15 / 3) × 0.5 = 2.5 feets

The new location of the diver can be obtained thus :

Initial depth - height climbed

New location = 10 feets - 2.5 feets = 7.5 feets

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