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A publisher reports that 30% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 110 found that 20% of the readers owned a laptop. Determine the P-value of the test statistic. Round your answer to four decimal places.

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Answer:

Test statistic = - 2.29

Pvalue = 0.0110

Step-by-step explanation:

The hypothesis :

H0 : p = 0.3

H1 : p < 0.3

Test statistic :

z=pˆ−p/√p(1−p)/n

pˆ = 0.2

Z = (0.20 - 0.30) / √(0.30(1 - 0.30) / 110

Z = - 0.1 / √0.0019090

Z = - 0.1 / 0.0436931

Z = - 2.29

Test statistic = -2.29

The Pvalue :

P(Z < -2.29) = 0.0110

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