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At 2:00, Alice was traveling in a car at 40 miles/hour. She then slows down, and at 4:00, she was traveling at 20 miles/hour.


What was Alice’s average acceleration between 2:00 and 4:00?
Show your complete calculation and state your answer with the correct units.

Respuesta :

samueladesida43

Answer:

-10miles/hr²

Explanation:

a = ∆v/∆t

Where:

a = acceleration (miles/hr²)

∆V = change in velocity (miles/hr)

t = time (hour)

The change in time is from 2:00 - 4:00 ∆t = 2 hours.

The distance covered is as follows: 20miles/hour - 40 miles/hr

∆v = -20miles/hr

Using a = ∆v/∆t

a = -20/2

a = -10miles/hr²

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