Respuesta :

[tex]\begin{gathered} \int ^{16}_9(\sqrt[]{x}-4)dx \\ \int ^{16}_9(\sqrt[]{x}-4)dx=\int ^{16}_9\sqrt[]{x}dx-\int ^{16}_94dx \\ \int ^{16}_9\sqrt[]{x}dx=\frac{2x^{\frac{3}{2}}}{3}\mleft\{\begin{aligned}16 \\ 9\end{aligned}=\frac{74}{3}\mright. \\ \int ^{16}_94dx=-4x\mleft\{\begin{aligned}16 \\ 9\end{aligned}\mright.=-28 \\ \int ^{16}_9(\sqrt[]{x}-4)dx=\frac{74}{3}-28=-\frac{10}{3} \end{gathered}[/tex]

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