Eliminate the parameter t to find a cartesian equation for x=t^2 y=2+10t

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04-08-2017
Mathematics

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Eliminate the parameter t to find a cartesian equation for x=t^2 y=2+10t

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What value of x makes the equation true ? 4(2x-4)=16

ghanami ghanami · Answer 1 · 2017-08-04T11:31:50+02:00

ghanami ghanami

04-08-2017

hello :
[tex] \left \{ {{x= t^{2} }...(1) \atop {y=2+ 10t }...(2)} \right. [/tex]
by(1) :
[tex]t = \frac{y-2}{10} [/tex]
subsct in (2) :
[tex]x = ( \frac{y-2}{10} )^{2} [/tex]....(cartesian equation )

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